SOLUTION: There were some red yellow and blue toy cars in a box. 3/8 of the toy cars were red and 26 were blue. The rest were yellow. If there were 12 fewer yellow toy cars than blue toy car

Question 1187316: There were some red yellow and blue toy cars in a box. 3/8 of the toy cars were red and 26 were blue. The rest were yellow. If there were 12 fewer yellow toy cars than blue toy cars, how many red toy cars were there.
Thanks

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
This is incomplete work but enough for you to figure what to do.

RED r YELLOW y BLUE 26 Total r+y+26

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Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
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There were some red, yellow, and blue toy cars in a box.
3/8 of the toy cars were red and 26 were blue. The rest were yellow.
If there were 12 fewer yellow toy cars than blue toy cars, how many red toy cars were there?
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Read the condition attentively. 26 cars were blue and 12 fewer than blue were yellow: so there were 26-12 = 14 yellow cars. The blue cars PLUS yellow cars comprise 26 + 14 = 40 cars, and this amount is = 5/8 of the total number of cars. Hence, 1/8 of the total cars is 40:5 = 8. THEREFORE, the number of RED cars is three times 8, which is 3*8 = 24. ANSWER

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This problem admits easy mental solution, without using any equations.

So, it SHOULD be solved by the simplest way, as the common sense dictates it . . .

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