SOLUTION: find a 2 digit number whose tens digit is 3 less than the units digit. The orginal number is 6 more than 4 times the sum of the digit

Question 118600: find a 2 digit number whose tens digit is 3 less than the units digit. The
orginal number is 6 more than 4 times the sum of the digit
Answer by wgunther(43) (Show Source): You can put this solution on YOUR website!
So, let a be the tens digit, and b be the unit digit.
a+3=b
10a+b=6+4(a+b)
So, putting this in a workable form
a-b=-3
6a-3b=6

Solved by pluggable solver: Linear System solver (using determinant)

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(a=5, b=8}

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