SOLUTION: A dentist places a gold filling in the shape of a cylinder with a hemispherical top in a patient's tooth. The radius of the filling is 3 mm. The height of the cylindrical portion i

Question 118546: A dentist places a gold filling in the shape of a cylinder with a hemispherical top in a patient's tooth. The radius of the filling is 3 mm. The height of the cylindrical portion is 4 mm. If dental gold costs $16.00 per cubic millimeter, how much did the gold for the filling cost? Round to the nearest cent. Use π ≈ 3.14.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A dentist places a gold filling in the shape of a cylinder with a hemispherical top in a patient's tooth. The radius of the filling is 3 mm. The height of the cylindrical portion is 4 mm. If dental gold costs $16.00 per cubic millimeter, how much did the gold for the filling cost? Round to the nearest cent. Use π ≈ 3.14.
:
Cost = 16*cylinder volume + 16*hemisphere volume
:
Cost = 16(pi*3^2*4) + 16(.5*pi*3^2) = 2,035.75
:
I used Calculator pi, so it may be slightly different, if you use 3.14.
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