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someone thinks he can shoot an arrow as high as the Willis Tower in Chicago (443 m high).
(a) at what velocity would the arrow have to be released at ground level?
(b) how long would the ascent take?
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(a) The general formula to calculate the required initial vertical velocity of ascent " v " is
v = ,
where h is the maximum height in meters, g is the gravity acceleration g = 9.81 m/s^2.
For h = 443 meters (your example)
v = = 93.229 m/s.
(b) For the ascent time, use the formula and get the answer
t = = = 9.5 seconds (rounded).
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