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In a 100m race the winning time was 9.95 seconds. If the second place had a time of 10.04 seconds
how far behind the winner was the second place when the winner crossed the finish line.
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The rate of the second place runner was r = = 9.96 meters per second = 9.96 m/s.
At the time t = 9.95 seconds, when the first place runner completed the distance,
the second place runner covered 9.96 m/s * 9.95 s = 99.102 meters.
Hence, the second place runner was 100 - 99.102 = 0.898 of a meter behind the winner, when the winner crossed the finish line.
Solved.