SOLUTION: A circular garden with a radius of 8' is divided into quadrants with walkways 2' wide. The garden also has a circular walkway 2' wide on the exterior. Bricks 2 1/4" by 4" by 8 1/

Question 1177947: A circular garden with a radius of 8' is divided into quadrants with walkways 2' wide. The garden also has a circular walkway 2' wide on the exterior. Bricks 2 1/4" by 4" by 8 1/4" are used for the walkways. Bricks are placed flat. Determine number of bricks used.
Not sure how to solve.
Found 2 solutions by mananth, greenestamps:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

.
Area of circular walkway = area of outer circle - area of inner circle
= 3.14 ( 10^2-8^2)
= 3.14 * 36
=113.04 ft^2
Now we have to add the area of walkway in between the quadrants
(6*2)* 4 = 48
area of central square =4ft^2
Total bricked area = 52+113.04 = 165ft^2
Area of brick = 0.69 * 0.33 = =0.23 ft^2
Number of bricks = 165/0.23 = 718 bricks

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The solution from the other tutor needs a small correction....

The diameter of the garden is 16 feet; the walkways are 2 feet wide. So the rectangular sections of walkway are 7 feet long, not 6 feet.

So the total area of the interior walkways, consisting of the four rectangular sections and the central square, is (4*2*7)+2^2 = 60 square feet.

Then work the rest of the problem the way that other tutor does.

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