SOLUTION: A leaking faucet dripping once per second can waste x gal. per year. Determine amt. Year = 31536000 sec. 31536000 drips per year. Not sure how to solve.

Question 1176250: A leaking faucet dripping once per second can waste x gal. per year. Determine amt.
Year = 31536000 sec.
31536000 drips per year.
Not sure how to solve.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Since they don't tell you how much is in a drip, you've gone as far as you can with the problem....

Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
.

Simply multiply the number of seconds in an year by the volume of one single droplet.

About the volume of a droplet, learn from this Wikipedia article
https://en.wikipedia.org/wiki/Drop_(unit)#:~:text=The%20minim%20was%20defined%20as,%2C%2020%20drops%20per%20milliliter).

From the article, you will learn that this unit of volume is NOT WELL DEFINED :
it depends on many factors (on viscosity of the liquid and on its surface tension, as major factors).

Since the problem is NOT CORRECTLY defined from the very beginning, it is not
a classic Math problem in the standard understanding of this term.

It is, rather, the field for a curios person to conduct his (or her) own research/investigation.

THUS I outlined the issue for you,
and if you REALLY ARE a curious person, then this task is just for you --- and not for us, the tutors.

In any case, by writing these lines, I just completed my job as a tutor.

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