SOLUTION: Hi
The total perimeter of two squares of different sizes is 68cm. The total area of both squares 157 cm squared. What is the length of the bigger square.
Thanks
Algebra.Com
Question 1175842: Hi
The total perimeter of two squares of different sizes is 68cm. The total area of both squares 157 cm squared. What is the length of the bigger square.
Thanks
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
The workout:
Let and be the side lengths of the two squares
Start with two equations
--->
From here, substitute from the top eqn into the bottom:
Simplify, and factor
So -->
or --> <<< same answer, is simply the larger square for this solution
---
Check: 4*11 + 4*6 = 44 + 24 = 68
11^2 + 6^2 = 121 + 36 = 157
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