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There are some 20c coins in box A and some 50c coins in box B.
If 40 coins are transferred from A to B there will be the same amount of money in each box.
If 24 coins are transferred from B to A there will be 9 times as much money in A as in B.
How many coins are in each container ?
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Let A be the number of the 20c coins in box A, and
Let B be the number of the 20c coins in box A.
Then. following literally the problem's description, we can write these two equations
A - 40*20 = B + 40*20 (1) (second line of the problem condition, see above)
A + 24*50 = 9*(B-24*50) (2) (third line of the problem condition, see above)
Or, simplifying, you can write these equations in equivalent form
A - B = 1600 (3) (instead of equation (1) )
A - 9B = -12000 (4) (instead of equation (2) )
Now subtract equation (4) from equation (3). You will get
8B = 13600.
It implies B = = 1700.
Then from equation (3), A = 1600 + 1700 = 3300.
ANSWER. There are 3300 20c-coins in box A and 1700 50c-coins in box B.
Solved.