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Hi May spent 1/6 of her money on a dress and 2 blouses. The dress costs as much as 3 blouses.
She spends 3/4 of the remaining money on a watch. The watch costs $220.50 more than the dress.
How much did she have at first.
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Ignore the post by @gosgarithmetic, since his setup is INCORRECT.
Let x = How much she had at first (dollars).
She first spent 1/6 of her money - so, of her amount remained.
Taking into account that the dress costs as much as 3 blouses, we can write the system of equations in this form
= 3B + 2B (1)
= 3B + 220.50 (2)
Simplify
= 5B (3)
= 3B + 220.50 (4)
Multiply equation (3) by 6 (both sides). Multiply equation (4) by 24 (both sides). You will get
x = 30*B (5)
15x = 72B + 5292 (6)
From (5), substitute the expression for x into (6). You will get
15*30*B = 72*B + 5292
450*B - 72*B = 5292
378*B = 5292
B = 5292/378 = 14.
Then from (5) we get the FINAL ANSWER:
x = 30*14 = 420 dollars.
ANSWER. She had originally 420 dollars.
Solved.