SOLUTION: A projectile is launched from ground level with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s= -1
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Question 1164953: A projectile is launched from ground level with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s= -16t^2 + V0t . Find the time(s) that the projectile will (a) reach a height of 96 ft and (b) return to the ground when V0= 112 feet per second.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A projectile is launched from ground level with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s= -16t^2 + V0t .
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Find the time(s) that the projectile will (a) reach a height of 96 ft
s = h(t) = -16t^2 + 112t
-16t^2 + 112t = 96
Solve for t
2 times, ascending and descending.
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and (b) return to the ground when V0= 112 feet per second.
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-16t^2 + 112t = 0
Solve for t.
PS t = 0 at launch
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