And oil tanker can be emptied by the main pump in five hours in auxiliary pump can empty the same tanker in 11 hours if the main pump is started at 5 PM when should the auxiliary pump he started so that the tanker is emptied by 9 PM
Main pump can empty tank in 5 hours, or of tank in 1 hour
Auxiliary pump can empty tank in 11 hours, or of tank in 1 hour
Let time it takes auxiliary pump, along, with the main pump, to empty tank, be T
The tank needs to be emptied in 4 hours (5:00 p.m. - 9:00 p.m.), so main pump will be working for 4 hours, while auxiliary will be, for T hours.
We then get the following ENTIRE-JOB equation:
44 + 5T = 55 ------ Multiplying by LCD, 55
5T = 11
T, or time it takes auxiliary pump, along with main pump, to empty tank =
Now, subtract that time from 9:00 p.m. to get the time that the auxiliary pump needs to be turned on! Capeesh?