Letbe the reading of the slower clock; t be the normal clock reading (= actual time). Then from the condition = = = for any time interval t after 8:00 am. When this clock hits 12 at noon exactly, = 4; hense = , or = t - 8 = t-8 = t -8 t-8 = 4 hours + of an hour = 4 hours and 0.286 of an hour = 4 hours 17 minutes and 9.6 seconds. ANSWER. At this moment, the correct time is 17 minutes and 9.6 seconds after noon.