SOLUTION: A rectangular billboard sign has a length that is four yards longer than twice its width, x If the area of the sign is 30 square yards, which equation could be used to find the dim

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Question 1160885: A rectangular billboard sign has a length that is four yards longer than twice its width, x If the area of the sign is 30 square yards, which equation could be used to find the dimensions in yards of the sign?
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

A rectangular billboard sign has a length that is four yards longer than twice its width, x If the area of the sign is 30 square yards, which equation could be used to find the dimensions in yards of the sign?
if a billboard sign length is longer than twice its width we have
.........eq.1
if its area is , we have
........eq.2
substitute from eq.1 in eq.2
............solve for

...simplify, divide by
........ factor completely





=> ->
=> ->->disregard negative solution


go to .........eq.1, substitute




so, the dimensions of the rectangular billboard sign are:
the length:
the width:

Answer by ikleyn(52873)   (Show Source): You can put this solution on YOUR website!
.

    W*(2W+4) = 30  square yards (the area).


    W*(W+2)  = 15.


So, 15 is presented as the product of two factors that differ by 2.


Hence, guessing mentally,  W = 3;  W + 2 = 5.


    Or you can solve the equation (1) formally.


ANSWER.  W = 3 yards;  L = 2W + 4 = 2*3+4 = 10 yards.

Solved.


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