SOLUTION: Find the equation of the line tangent to the curve at the point defined by the given value of t.
{{{x=16sint}}}, {{{y=4cost}}}, {{{t=pi/4}}}
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Question 1156951: Find the equation of the line tangent to the curve at the point defined by the given value of t.
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of the line tangent to the curve at the point defined by the given value of t.
, ,
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---> @ pi/4 = 8sqrt(2)
---> @ pi/4 = 2sqrt(2)
dx/dt = 16cos(t) ---> @ pi/4 = 8sqrt(2)
dy/dt = -4sin(t) ---> @ pi/4 = -2sqrt(2)
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dy/dx = -sin(t)/(4cos(t)) = -tan(t)/4
@pi/4: dy/dx = -1/4
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