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Let x = original mass of silver in the alloy (in grams); y = mass of of copper.
After adding 25% of the original mass of silver, there are x+0.25x = 1.25x grams silver in the alloy.
From the condition, you have these two equations
x - y = 50 grams (1) (the difference of the original amounts)
= 0.6 (2) (silver concentration of 60% after adding)
Simplify equation (2)
1.25x = 0.6*(1.25x + y)
1.25x = 0.75x + 0.6y.
0.5x = 0.6y (3)
From equation (1), express x = 50 + y and substitute it into equation (3).
0.5*(50 + y) = 0.6y
25 + 0.5y = 0.6y
25 = 0.6y - 0.5y = 0.1y
y = 25/0.1 = 250.
Then from equation (1), x = 250 + 50 = 300.
ANSWER. Originally, the alloy was 300 gram solver and 250 grams copper.
Solved.
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