SOLUTION: Three numbers are such that the first is three times the second, and the third exceeds the first by 7. Their sum is 49. Determine the numbers
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Question 1155040
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Three numbers are such that the first is three times the second, and the third exceeds the first by 7. Their sum is 49. Determine the numbers
Answer by
josgarithmetic(39630)
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Just follow what the description is, literally.
first 3b second b third 3b+7 SUM 49
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