SOLUTION: If two construction teams work together, they can finish a road in 15 days. The rate of work of the first team is 4/5 of the rate of the second team.
How many days each team ne
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Question 1154864: If two construction teams work together, they can finish a road in 15 days. The rate of work of the first team is 4/5 of the rate of the second team.
How many days each team needs to complete this job alone?
Found 2 solutions by mananth, VFBundy:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
If two construction teams work together they can finish a road in 15 days.the rate of work of the first team is 4/5 of the rate of the second team.
How many days each team needs to complete this job alone.
Let one team take x hours to do the job
This team does 1/x of the job in 1 hour alone
They take (4/5)x hours to do the job
This team does (5/4x) of the job in 1 hour alone
Both together do the job in 15 days
Together the complete 1/15 of the job in1 hour
AMP Parsing Error of [((9/4x)=1/15 ]: Invalid expression. Closing bracket expected =1/15 at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187.
.
4x = 135
x =135/4
x =33.75
First team 33.75 days
II team
(4/5)*33.75 =27 days
Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website!
Rate of work of first team = =
Rate of work of second team =
Rate of work working together = = --> = --> = --> -->
Plug in x = 27:
Rate of work of first team = = =
Rate of work of second team = =
Since the first team completes 4/135 of the job per day, this means it will take them 135/4 days...or 33.75 days...to complete the job working alone.
Since the second team completes 1/27 of the job per day, this means it will take them 27 days to complete the job working alone.
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