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From the condition, you have this system of 2 equations in 2 unknowns
x + y = 290 (1) (total number of tickets)
8x + 4y = 1440 (2) (total money)
where x = # of adult tickets, y = # of student tickets.
From equation (1), express y = 290-x and substitute it into equation (2), replacing y. You will get then
8x + 4*(290-x) = 1440.
From the last equation
x = = 70.
ANSWER. 70 adult tickets and 290-70 = 220 student tickets.
CHECK. 8*70 + 4*220 = 1440 dollars. ! Correct !
Solved.
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It is a standard tickets problem.
There are different methods of solving such problems.
In this site, there are lessons
- Using systems of equations to solve problems on tickets
- Three methods for solving standard (typical) problems on tickets
explaining and showing all basic methods of solving such problems.
From these lessons, learn on how to solve such problems once and for all.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.