SOLUTION: NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+217t+185. Assuming that the rocket will splash down

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Question 1153455: NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+217t+185.
Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
The rocket splashes down after ________ seconds.
How high above sea-level does the rocket get at its peak?
The rocket peaks at __________ meters above sea-level.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

NASA launches a rocket at seconds. Its height, in meters above sea-level, as a function of time is given by

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
will occur when
.........use quadratic formula




solutions: we need only positive solution






The rocket splashes down after ________ seconds.

How high above sea-level does the rocket get at its peak?

max occurs when


The rocket peaks at __________ meters above sea-level.

Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
.

In my post, I only want to explain to the visitor, that the given equation DOES NOT describe the flight of a real rocket.


It describe the flight of a PROJECTILE, i.e. an object launched with the initial velocity of 217 m/s,


but then falling freely under the Earth's gravitation force.


The drag force, which provides vertical acceleration of a real rocket,  ABSENTS in the given equation (!)


So, it is not a real rocket (!) (!)


Such object has a common name "a projectile" in Physics.


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