1/10. It's just as likely that any one will show up first as any other. Let p = the probability that any one will show up first: P(#1 will show up first) = p P(#2 will show up first) = p P(#3 will show up first) = p P(#4 will show up first) = p P(#5 will show up first) = p P(#6 will show up first) = p P(#7 will show up first) = p P(#8 will show up first) = p P(#9 will show up first) = p P(#10 will show up first) = p ----------------------------- 10p = 1 p = 1/10 Edwin
, based on common sense.