SOLUTION: The student council is hosting a drawing to raise money for scholarships. They are selling tickets for $7 each and will sell 500 tickets. There is one $1,000 grand prize, two $200
Question 1150251: The student council is hosting a drawing to raise money for scholarships. They are selling tickets for $7 each and will sell 500 tickets. There is one $1,000 grand prize, two $200 second prizes, and fourteen $10 third prizes. You just bought a ticket. Find the expected value for your profit. Round to the nearest cent. Found 4 solutions by VFBundy, Boreal, ikleyn, greenestamps:Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website! Odds of winning grand prize = 1/500
Odds of winning second prize = 2/500
Odds of winning third prize = 14/500
Odds of not winning any prize = 483/500
You must also remember that it costs $7 for the ticket, so if you win the $1000 grand prize (for example), you're really only winning $993. Same goes for any of the prizes.
1/500 * 993 = 993/500
2/500 * 193 = 386/500
14/500 * 3 = 42/500
483/500 * -7 = -3381/500
993/500 + 386/500 + 42/500 - 3381/500
= -1960/500
= -98/25
= -$3.92 Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website! E(x)=sum x*p(x)
=(1000-7)(1/500)+(200-7)(2/500)+(10-7)(14/500)-7(483/500), because $7 to play in the first place has to come out of the winning.
=993/500+386/500+42/500-3381/500
=-1960/500
=-$3.92 (loss) Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website! .
The expected value for your profit is - 7 = - 7 = - 7 = 3.08 - 7 = -3.92 dollars per game.
In other words, be ready to lose $3.92 in average, if you play many times this game, buying every time 1 ticket from 500.