Question 1146667: At Frank's Auto Plaza there are currently 10 new cars, 4 used cars, 12 new trucks, and 5 used trucks. Frank is going to choose one of these vehicles at random to be the Deal of the Month. What is the probability that the vehicle that Frank chooses is used or is a car?
Do not round intermediate computations, and round your answer to the nearest hundredth.
Found 3 solutions by Alan3354, ikleyn, MathTherapy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! At Frank's Auto Plaza there are currently 10 new cars, 4 used cars, 12 new trucks, and 5 used trucks. Frank is going to choose one of these vehicles at random to be the Deal of the Month. What is the probability that the vehicle that Frank chooses is used or is a car?
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10 + 4 + 12 + 5 = 31 vehicles
9 used
14 cars
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(9 + 14)/31
Answer by ikleyn(52783)  (Show Source):
You can put this solution on YOUR website! .
The total number of vehicles is 10 + 4 + 12 + 5 = 31.
It is the denominator of the fraction.
The subset "used" + "cars" has 10 (new cars) + 4 (used cars) + 5 (used trucks) = 19 elements.
It is the numerator of the fraction.
The probability under the question is  .
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
At Frank's Auto Plaza there are currently 10 new cars, 4 used cars, 12 new trucks, and 5 used trucks. Frank is going to choose one of these vehicles at random to be the Deal of the Month. What is the probability that the vehicle that Frank chooses is used or is a car?
Do not round intermediate computations, and round your answer to the nearest hundredth.
Let used be U, and car be C
Total vehicles: 10 + 4 + 12 + 5 = 31
Total used vehicles: 4 + 5 = 9
Total cars: 10 + 4 = 14
Total used cars: 4
Then we get: 
You now need to ROUND the above FRACTION to get your answer, in its stated format!
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