SOLUTION: An 18kg mass is placed at one end of a steel bar that is 1m long. A 35kg mass is placed at the other end. Where should the fulcrum be placed to balance the bar? If anyone can

Question 114613This question is from textbook Algebra Structure and Method
: An 18kg mass is placed at one end of a steel bar that is 1m long. A 35kg mass is placed at the other end. Where should the fulcrum be placed to balance the bar?
If anyone can help me solve this problem I would appreciate it!!!
Please and Thank You!!! This question is from textbook Algebra Structure and Method

Found 2 solutions by checkley71, scott8148:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
35X=18(1-X)
35X=18-18X
35X+18X=18
53X=18
X=18/53
.34 METERS FROM THE 35 KG MASS IS THE FULCRUM.
PROOF
.35*.34=18(1-.34)
.119=18*.66
.119=.119

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
for the bar to balance; the products of the masses and their distances from the fulcrum must be equal
___ (m1)(d1)=(m2)(d2)

let x="35 kg distance", so 1-x="18 kg diatance"

35x=18(1-x) ___ 35x=18-18x ___ 53x=18
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