SOLUTION: Consider the equation 7x^2-8x+3=0. (a) Find and state the value of the discriminant, b2 - 4ac. Then state whether one real-number solution, two different real-number solution

Question 1146017: Consider the equation 7x^2-8x+3=0.
(a) Find and state the value of the discriminant, b2 - 4ac. Then state whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exists. Show work.

(b) Find the exact solutions of the equation. Simplify as much as possible. Show work. You are welcome to use any of the techniques which apply and that you prefer except graphing (i.e., factoring, applying the principle of square roots, completing the square, or the quadratic formula).

Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
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equation ax^2+bx+c=0.
(a) Find and state the value of the discriminant, b^2 - 4ac.
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If discriminant is negative, no real solutions
If discriminant is 0, then exactly one real solution
If discriminant is positive, then two real solutions

You do the substitutions for part (a) and decide.
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