SOLUTION: Rupert drove home at an average rate of 625 mph. Find his rate in feet per second. Round to the nearest 10th

Question 1145992: Rupert drove home at an average rate of 625 mph. Find his rate in feet per second. Round to the nearest 10th
Found 5 solutions by Theo, josgarithmetic, MathTherapy, ikleyn, Alan3354:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
his rate is 625 miles per hour.
the number of seconds in on hour is equal to 60 * 60 = 3600.
the rate per second is therefore 625 / 3600 = .173611111..... miles per second.
there are 5280 feet in a mile, therefore the rate is .17361111... * 5280 = 916.6666666..... feet per second.

this could all be done in one shot by taking 625 and multiplying it by 5280 and then dividing it by 3600 to get 916.6666666... feet per second.

round to the nearest 10th to get 916.7 feet per second.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

Simplify that.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Rupert drove home at an average rate of 625 mph. Find his rate in feet per second. Round to the nearest 10th

5,280 feet = 1 mile 3,600 seconds = 1 hour
Dimensional analysis method:
Just complete the calculation, manually or using a calculator!.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Rupert drove home at an average rate of 625 mph. Find his rate in feet per second. Round to the nearest 10th
~~~~~~~~~~~~~~~~~

Drove home at the average rate of 625 mph ?

    O-o-o, mamma mia . . .

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
It's a conversion, not a math problem.
Look it up.
=================
I hope Rupert drove above 10,000 feet.
The speed limit below 10,000 feet is 250 knots, 288 mi/hr.
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PS The nearest 10th is October 10th.

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