SOLUTION: An inch of rain on an acre of land weighs n amt. Determine weight. A cu. ft. of water = 7.5 gal., weighs 62.5 lbs. 1 in. = .083333 ft. .083333 * 43560 = 3269.985 cu.

Question 1145936: An inch of rain on an acre of land weighs n amt. Determine weight.
A cu. ft. of water = 7.5 gal., weighs 62.5 lbs.

1 in. = .083333 ft.

.083333 * 43560 = 3269.985 cu. ft.

3269.985 * 7.5 = 24524.88 gal.
24524.88 * 62.5 = 1532805 lbs. = 766.40 tons

Where did I miscalculate?

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Density Water, 62.4 pounds per cubic foot
One Acre, 43560 square feet
1 foot is 12 inches.

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An inch of rain on an acre of land weighs n amt. Determine weight.
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One-twelfth feet of rain on an acre of land weighs n amt. Determine weight.
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This VOLUME is .

The entire setup could be:

partly simplified,
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
An inch of rain on an acre of land weighs n amt. Determine weight.
A cu. ft. of water = 7.5 gal., weighs 62.5 lbs.
1 in. = .083333 ft.
.083333 * 43560 = 3269.985 cu. ft.
3269.985 * 7.5 = 24524.88 gal.
24524.88 * 62.5 = 1532805 lbs. = 766.40 tons
Where did I miscalculate?
================
You used gallons instead of cubic feet.
There's no reason to convert to gallons.

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