SOLUTION: A human gene carries a certain disease from the mother to the child with a probability rate of 47%. That is, there is a 47% chance that the child becomes infected with the disease

Question 1143041: A human gene carries a certain disease from the mother to the child with a probability rate of 47%. That is, there is a 47% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another. Find the probability that all three of the children get the disease from their mother.
a. 0.149
b. 0.896
c. 0.132
d. 0.104
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
For all three to get it, the probability is 0.47^3, because of independence. That is 0.104
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