SOLUTION: A ferris wheel is 60 meters in diameter and boarded at its lowest point (6 O'Clock) from a platform which is 6 meters above ground. The wheel makes one full rotation every 18 minut

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Question 1142925: A ferris wheel is 60 meters in diameter and boarded at its lowest point (6 O'Clock) from a platform which is 6 meters above ground. The wheel makes one full rotation every 18 minutes, and at time t=0 you are at the loading platform (6 O'Clock). Let h=f(t) denote your height above ground in meters after t minutes.
What is the midline of the function h=f(t)?


Write a function f(t) that describes the height of the passenger as a function of time. f(t)=

Answer by ikleyn(52817)   (Show Source): You can put this solution on YOUR website!
.

(a)  Middle line of the function h = f(t) = the height of the center of the ferris wheel = 6 + 60/2 = 6 + 30 = 36 meters.



(b)  The period of rotation is 18 minutes; so the wheel turns   = 20 degrees per minute.


     The condition does not say if the wheel rotates clockwise or anti-clockwise.


     If it rotates clockwise, the current angle is   = 270 - 20*t degrees, where t is the time in minutes.


     Then the height function  h = f(t) =  = .



     If the wheel rotates anti-clockwise, the current angle is   = 270 + 20*t degrees.


     Then the height function  h = g(t) =  = .



     If you look into these height functions, you will see that actually 


        f(t) = g(t)


    independently of the direction of rotation. So, in both cases


        h = f(t) =  = g(t) = .


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