SOLUTION: 3/5 of the number of pens displayed at the bookstore were red and the rest were blue.After 260 red pens, and 1/4 of the blue pens were sold, 1/2 of the pens were left.How many pens
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Question 1141187: 3/5 of the number of pens displayed at the bookstore were red and the rest were blue.After 260 red pens, and 1/4 of the blue pens were sold, 1/2 of the pens were left.How many pens were displayed at the bookstore first?
Can you please help me how to solve this by equation??
Thanks in advance Found 3 solutions by josgarithmetic, rothauserc, ankor@dixie-net.com:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! let x be the number of pens displayed at the bookstore first
:
3x/5 are red, 2x/5 are blue
:
260 + (2x/5)/4 = x/2
:
260 + (2x/20) = x/2
:
5200 +2x = 20x/2
:
10400 +4x = 20x
:
16x = 10400
:
x = 650
:
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there were 650 pens at first
:
check the answer
:
there are 390 red at first and 260 blue at first
:
260 + (260/4) = (650/2)
:
260 + 65 = 325
:
325 = 325
:
answer checks
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:
You can put this solution on YOUR website! 3/5 of the number of pens displayed at the bookstore were red and the rest were blue.
let p = total no. of pens
then p = no. of red pens
and p = no. of blue
:
After 260 red pens, and 1/4 of the blue pens were sold, 1/2 of the pens were left.
260 + *p = p
260 + = p
reduce fraction
260 + p = p
get rid of denominator, multiply by 10
2600 + p = 5p
2600 = 5p - p
2600 = 4p
p = 2600/4
p = 650
:
How many pens were displayed at the bookstore first? 650