SOLUTION: Just looking for a check to make sure I'm on the right track. Thanks 35. Given a line with equation 5x+2y=6, write an equation in point-slope form of the line perpendicular to t

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Question 1140458: Just looking for a check to make sure I'm on the right track. Thanks
35. Given a line with equation 5x+2y=6, write an equation in point-slope form of the line perpendicular to the given line through the point (4, -4).
5x+2y=6
5x -5x +2y=6 -5x
2y/2 = (-5x + 6)/2
y = -5/2x +3
y−y0=m(x−x0) m = 2/5
y - (-4) = 2/5(x - 4)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621)   (Show Source): You can put this solution on YOUR website!
Given line 5x+2y=6

Line perpendicular to given line has slope negative reciprocal of that of given line.


-
Given line, slope .

Slope for a line perpendicular to given line is .

The perpendicular line goes through (4,-4).
Equation for it is
OR .
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Just looking for a check to make sure I'm on the right track. Thanks
35. Given a line with equation 5x+2y=6, write an equation in point-slope form of the line perpendicular to the given line through the point (4, -4).
5x+2y=6
5x -5x +2y=6 -5x
2y/2 = (-5x + 6)/2
y = -5/2x +3
y−y0=m(x−x0) m = 2/5
y - (-4) = 2/5(x - 4)
Yes, you are on the right track!!

Great job!! 

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