SOLUTION: The semicircular turns of a horse race track
each have a radius of 200 feet. During the first turn of a race,
the lead horse is running near the inside rail on a path with a
202
Algebra.Com
Question 1139432: The semicircular turns of a horse race track
each have a radius of 200 feet. During the first turn of a race,
the lead horse is running near the inside rail on a path with a
202.0-foot radius, at a constant rate of 24.4 feet per second. A
second horse is rounding the same turn on a path with a 206.5-
foot radius. At what constant rate does the second horse need
to run to keep pace with the lead horse during this turn? Round
to the nearest tenth of a foot per second.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The semicircular turns of a horse Lrace track
each have a radius of 200 feet. During the first turn of a race,
the lead horse is running near the inside rail on a path with a
202.0-foot radius, at a constant rate of 24.4 feet per second. A
second horse is rounding the same turn on a path with a 206.5-
foot radius. At what constant rate does the second horse need
to run to keep pace with the lead horse during this turn? Round
to the nearest tenth of a foot per second.
----------------------
Linear speed = r * angular speed (in radians)
All exponents are 1, so it's proportional.
24.4/202 = v/206.5
v = 206.5*24.4/202
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