SOLUTION: A rectangular turtle pen is 6 feet long
by 4 feet wide. The pen is enlarged by
increasing the length and width by an equal
amount in order to double its area. What are
the dime
Algebra.Com
Question 1139342: A rectangular turtle pen is 6 feet long
by 4 feet wide. The pen is enlarged by
increasing the length and width by an equal
amount in order to double its area. What are
the dimensions of the new pen?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A rectangular turtle pen is 6 feet long by 4 feet wide.
The pen is enlarged by increasing the length and width by an equal
amount in order to double its area.
What are the dimensions of the new pen?
:
Find double the area of the pen
2(6*4) = 48 sq/ft
let x = the amt increased to double the area
(x+6)*(x+4) = 48
FOIL
x^2 + 4x + 6x + 24 = 48
x^2 + 10x + 24 - 48 = 0
x^2 + 10x - 24 = 0
factors to:
(x-2)(x+12) = 0
the positive solution is all we want here
x = 2
the new dimensions:
(2+6) = 8
(2+4) = 6
8 ft by 6 ft is the new dimensions
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