SOLUTION: Determine weight of a block of marble, which contains 130.71 ft.^3 and specific gravity of 2.742. Density = Mass / Volume Unsure how to solve.

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Question 1134668: Determine weight of a block of marble, which contains 130.71 ft.^3 and specific gravity of 2.742.
Density = Mass / Volume
Unsure how to solve.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
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Determine weight of a block of marble, which contains 130.71 ft.^3 and specific gravity of 2.742.
Density = Mass / Volume
Unsure how to solve.
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Abbreviating,

and you are given D is 2.742 times that of water and V=130.71 cubic feet.
------- The question asks for M.



Density for water is about 1 gram per cubic centimeter. You want to know or find the density of marble in POUNDS per CUBIC FOOT.

--
Density of water:





-----------density of water, in pounds per cubic foot.


Density of marble:




-

Finding the mass of the marble block:





Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.

Your problem, as it is formulated and presented, has an "underwater stone".


The volume is given in cubic feet, while the specific gravity goes with no measuring unit, at all.


But I know "the numbers", and I know that 2.742 is the marble's specific gravity measured in g/cm^3 or tons/m^3.


Actually,  Weight = specific gravity * Volume,


but this formula assumes that all the values go with coherent (=consistent) units.


At this point I will stop my tales.


My impression is that you retrieve your problems from a VERY OLD source . . .



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