SOLUTION: In the lab Justin has two solutions that contain alcohol and is mixing them with each other. He uses 100 mili litters less of solution A than solution B. Solution A is 13% alcohol

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Question 1134515: In the lab Justin has two solutions that contain alcohol and is mixing them with each other. He uses 100 mili litters less of solution A than solution B. Solution A is 13% alcohol ana Solution B is 19% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 243 milliliters of pure alcohol?
Answer by ikleyn(52777)   (Show Source): You can put this solution on YOUR website!
.
Your balance equation for the pure alcohol volume is 


    0.19x + 0.13*(x-100) = 243   milliliters of the pure alcohol,


where x is the volume of the solution B in milliliters, which is the value under the problem's question.


As soon as you have setup the balance equation, the rest is just arithmetic.


    x =  = 800 milliliters.    ANSWER

------------------

It is a standard and typical mixture problem.

For introductory lessons covering various types of mixture word problems see
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization,  from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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