SOLUTION: In a poker game, two people begin with equal sums of money. When the game ended, the loser had lost $50 more than a quarter of his money and the winner had twice as much money as

Question 113447This question is from textbook
: In a poker game, two people begin with equal sums of money. When the game ended, the loser had lost $50 more than a quarter of his money and the winner had twice as much money as the loser. How much money did each person have at the end of the game? This question is from textbook

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let x be the amt. each started with.
The loser lost x/4+50.
Combined holdings always total 2x.
x-(x/4+50)+2(x-(x/4+50))=2x
x-x/4-50+2(x-x/4-50)=2x
x-x/4-50+2x-2x/4-100=2x
4x-x-200+8x-2x+-400=8x multiply each side by 4 to eliminate fractions.
9x-600=8x
x=$600 what they each started with.
Loser had 600-(600/4+50)
=600-(150+50)
=600-200=$400.
The winner had 2*400=$800.
Ed
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