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Let start with the system from your post
B = 14685 (1)
14685 + T + L = 16070 (2)
14685 + A + L = 15580 (3)
14685 + A + T = 15925 (4)
We have 4 independent linear equations in 4 unknown, so the solution does exist, for sure.
The system has very special structure, and I will show you VERY SPECIAL trick to easy solve it, which works PERFECTLY for this structure.
First, subtract the value 14685 from both sides of each equation (2), (3) and (4). You will get
T + L = 16070 - 14685 = 1385 (5)
A + L = 15580 - 14685 = 895 (6)
A + T = 15925 - 14685 = 1240 (7)
The trick starts from this point.
First, add all three the equations (5), (6) and (7). You will get
2T + 2A + 2L = 1385 + 895 + 1240 = 3520, or, dividing by 2 both sides,
T + A + L = 1760 (8)
Now subtract equation (5) from equation (8). You will get
A = 1760 - 1385 = 375.
Next, subtract equation (6) from equation (8). You will get
T = 1760 - 895 = 865.
Finally, subtract equation (7) from equation (8). You will get
L = 1710 - 1240 = 520.
The problem is just solved. The ANSWER is
$375 for A; $865 for T, and $520 for L.
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If you want to see other similar solved problems, look into my lesson
- The tricks to solve some word problems with three and more unknowns using mental math
in this site.
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How do you set up the equation here? A recent basic model of a particular automobile had a price of $14,685. The basic model with the added features of automatic transmission and power locks was $16,070. The basic model with air conditioning and power locks was $15,580. The basic model with AC and automatic transmission was $15,925. What was the individual cost of each of the three options?
i have:
Basic = $14,685
B+T+L= $14,685 + T + L = $16070
B+A+L= $14,685 + A + L = $15,580
B+A+T = $14,685 +A+T = $15,925
What is the next step?
Using your equations:
14,685 + T + L = 16,070_____T + L = 16,070 - 14,685_____T + L = 1,385 ----- eq (i)
14,685 + A + L = 15,580_____A + L = 15,580 - 14,685_____A + L = 895 ----- eq (ii)
14,685 + A + T = 15,925_____A + T = 15,925 - 14,685_____A + T = 1,240 ----- eq (iii)
Subtract eq (i) from eq (ii) to get:....................A - T = - 490 ----- eq (iv)
Add eqs (iv) & (iii) to get:...........................2A = 750
A, or cost of automatic transmission =
I'm sure you'll be able to find the other costs.