.
Let "n" be the number of chickens he bought (the value under the question).
Then the price for one chicken is .
Had he bought (n+5) chickens for the same money, the price for one chicken in this hypothetical case would be .
From the condition,
- = 2.
It is your basic equation to solve.
Looking into the equation, you can guess its solution mentally and momentarily: n = 10.
To solve it algebraically, multiply both sides by n*(n+5). You will get
60*(n+5) - 60n = 2n*(n+5)
60n + 300 - 60n = 2n^2 + 10n
2n^2 + 10n - 300 = 0
n^2 + 5n - 150 = 0
(n-10)*(n+15)) = 0.
Of two roots n= 10 and n= -15, only positive n= 10 is meaningful.
Answer. n= 10 chickens.
Solved.
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To see many other similar solved problems, look into the lessons
- Challenging word problems solved using quadratic equations
- Had they sold . . .
in this site.
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