SOLUTION: Having a real hard time with this...please help! Solve system of equation word problem but either addition method or substitution method. George has two investments that yiel

Question 113154This question is from textbook
: Having a real hard time with this...please help!
Solve system of equation word problem but either addition method or substitution method.
George has two investments that yield a total of $185.60 in annual interest. The amount invested at 8% is $320 less than twice the amount invested at 6%. How much is invested at each rate?
Amount invested at 8% _________
Amount invested at 6% _________ This question is from textbook

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve system of equation word problem but either addition method or substitution method.
George has two investments that yield a total of $185.60 in annual interest. The amount invested at 8% is $320 less than twice the amount invested at 6%. How much is invested at each rate?
:
Let x = amt invested at 6%; Let y = amt invested at 8$
:
It says,
" The amount invested at 8% is $320 less than twice the amount invested at 6%."
Therefore:
y = (x - 320)
:
It also says,
"George has two investments that yield a total of $185.60 in annual interest."
.06x + .08y = 185.60
:
We can substitute (x-320) for y in the above equation:
.06x + .08(x-320) = 185.60
:
.06x + .08x - 25.6 = 185.6; multiplied what's inside the brackets
:
.06x + .08x = 185.60 + 25.6; added 25.6 to both sides
:
.14x = 211.2
:
x = 211.2/.14
:
x = $1508.57 invested at 6%
:
then
1508.57 - 320 = $1188.57 invested at 8%
:
:
It's a good idea to check our solution in the original interest equation:
.06(1508.57) + .08(1188.57) =
90.51 + 95.09 = 185.60
:
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