SOLUTION: Find the number of different ways that the nine players on a baseball team can lineup

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Question 1127705: Find the number of different ways that the nine players on a baseball team can lineup
Found 3 solutions by Alan3354, stanbon, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The 1st is 1 or 9.
then 1 of 8
etc
--> 9! ways
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find the number of different ways that the nine players on a baseball team can lineup
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Answer:: 9P9 = 9! = 9*8*7*...*2*1 = 362880 ways
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Cheers,
Stan H.
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
Any of 9 players can stand first.                (9 options)

Any of remaining 8 players can stand second.     (8 options)

Any of remaining 7 players can stand third       (7 options)

    . . .    and so on   . . . 


In all, there are  9*8*7*6*5*4*3*2*1  ways = 9! ways = 362880 ways to form different lineup.

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It is the number of all possible permutations of 9 objects.

On Permutations,  see the lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations

    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


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