SOLUTION: A farmer Bought a number of pigs for $26. However 4 of them dies before he could sell the rest at a profit of 10 per pig. His total profit was $198. How many pigs did he originally

Question 1125879: A farmer Bought a number of pigs for $26. However 4 of them dies before he could sell the rest at a profit of 10 per pig. His total profit was $198. How many pigs did he originally buy?

The equation I came up with but when solved i do not get the correct answer:
N= number of pigs
P=price
np=216
(n-4)(p+10)=198
So ,
p=(216)/x
Plugged in
(n-4)*((216)/x+10)=198

Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Depends. Did he buy pigs for $26 each or pigs for a total of $26? Not that it makes any difference because there is no integer solution either way -- and you can't, to my knowledge, by a fraction of a pig.

John

My calculator said it, I believe it, that settles it

Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.

In your condition, I see the number $26.

In your solution, I see the number 216.

After that, I do not believe any single word and any single number in your post.

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