SOLUTION: What is the simplified version of these complex expressions? https://imgur.com/hZhImbP

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Question 1122268: What is the simplified version of these complex expressions?
https://imgur.com/hZhImbP

Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Write ONE of your examples HERE, instead of giving a hyperlinked picture showing all the exercises which you want done.

The item c:
Learn to use plain text in this algebra.com system.
()/()

and then
(1/a+2/b)/(()/())

and then
(1/a+2/b)/((a+1)/(ab))

Now put the triple brackets tags around the expression.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




The common denominator in both the numerator sum and the denominator sum is just the product of the two denominators, . Being a conjugate pair, the product is the difference of two squares, . So:



Notice that both the numerator fraction and the denominator fraction both have the same denominator, so that just goes away.



Now, being very careful with your signs, just collect like terms throughout and you are done.

By the way, I only did the first one because you only get one problem per post. But if you use the same methods, you should be able to do the other two yourself.


John

My calculator said it, I believe it, that settles it


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