SOLUTION: Given that y=k(x^2+15)^1/2 , where k is a constant, the variables x and y vary such that when x=1, the rate of increase of x with respect to time is 3 times the rate of increase of
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Question 1122161: Given that y=k(x^2+15)^1/2 , where k is a constant, the variables x and y vary such that when x=1, the rate of increase of x with respect to time is 3 times the rate of increase of y with respect to time. Find the value of k.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I think this is right, but don't go making any large wagers.
^{1/2})
\ =\ \frac{2xk}{2\sqrt{x^2\,+\,15}}x'(t))
But }{x'(t)}\ =\ \frac{1}{3})
when 
, so:
k}{2\sqrt{(1)^2\,+\,15}}\ =\ \frac{1}{3})
John
My calculator said it, I believe it, that settles it
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i would really be thank u if u could help me out with this. thank so much
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