SOLUTION: The motion of the ball thrown vertically in the air is described by f(t)=-16t^2+96t+10. What is the maximum height above the ground the ball will reach, and how many seconds will

Question 1120634: The motion of the ball thrown vertically in the air is described by
f(t)=-16t^2+96t+10. What is the maximum height above the ground the ball will reach, and how many seconds will pass before it reaches this height?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The motion of the ball thrown vertically in the air is described by
f(t)=-16t^2+96t+10. What is the maximum height above the ground the ball will reach, and how many seconds will pass before it reaches this height?
--------
It's a parabola.
The max height is the vertex, at t = -b/2a
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Can you do the rest?
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