SOLUTION: A rectangular box with a square base and open top is to be made. Find the volume of the largest box that can be made from 432 sq. m. of material.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A rectangular box with a square base and open top is to be made. Find the volume of the largest box that can be made from 432 sq. m. of material.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1119872: A rectangular box with a square base and open top is to be made. Find the volume of the largest box that can be made from 432 sq. m. of material.
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39629) About Me  (Show Source):
You can put this solution on YOUR website!
x by x base
y height
v, the volume

system%28x%5E2%2B4xy=432%2Cv=y%2Ax%5E2%29

Substitute for y in v, simplify, and look for the minimum point of v.

Answer by ikleyn(52873) About Me  (Show Source):
You can put this solution on YOUR website!
.
In a way on how this post is worded and presented, it is not a Math problem at all.

So, it does not deserve any serious consideration.

To become a Math problem, it needs to be totally re-formulated.

I know how to do it, but I think it is not my job and function to formulate it for / (instead of) you.

In opposite, it is YOUR DUTY to bring clear and correct formulation.



Answer by greenestamps(13208) About Me  (Show Source):
You can put this solution on YOUR website!


Let the side of the square base be x and the height be h. Then

(1) the total surface area (base and 4 sides) in square meters is 432:
x%5E2%2B4xh+=+432

(2) the volume (to be maximized) is the area of the base times the height:
V+=+x%5E2h

Solve equation (1) for h and substitute in equation (2) to get an expression for the volume in terms of the single variable x:

4xh+=+432-x%5E2
h+=+%28432-x%5E2%29%2F4x
V+=+x%5E2%28%28432-x%5E2%29%2F4x%29+=+%28432x%5E2-x%5E4%29%2F4x+=+108x-x%5E3%2F4

Take the derivative and set it equal to 0 to find the value of x that maximizes the volume; and calculate the volume for that value of x:

108+-+%283%2F4%29x%5E2+=+0
%283%2F4%29x%5E2+=+108
x%5E2+=+144
x+=+12
V+=+108%2812%29-%2812%5E3%29%2F4+=+1296-432+=+864

The maximum volume is 864 cubic meters, when the square base is 12m on a side and the height is 6m.