SOLUTION: If s = t^3-5t^2+5t-3, when will the velocity be at 2?

Question 1119869: If s = t^3-5t^2+5t-3, when will the velocity be at 2?
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
velocity is ds/dt
ds/dt (t^3-5t^2+5t-3) is 3t^2-10t+5
when s=2, velocity will be -3

Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

s = t^3-5t^2+5t-3

v = ds/dt = 3t^2-10t+5

Solve to find when v = 2:

3t^2-10t+5 = 2
3t^2-10t+3 = 0
(3t-1)(t-3) = 0

The velocity will be 2 when t=1/3 and when t=3.

A graph of the velocity function, showing that v=2 at t=1/3 and at t=3:

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