SOLUTION: please explain.
b^2-2bc+c^2=(b-c)^2
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Question 111596: please explain.
b^2-2bc+c^2=(b-c)^2
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
please explain.
b^2-2bc+c^2=(b-c)^2
----------------------
I'll show you that the right side of the equation is the
same as the left side:
--------------
(b-c)^2
=(b-c)(b-c)
= b(b-c)-c(b-c)
=b^2-bc-bc+c^2
=b^2-2bc+c^2
==============
Cheers,
Stan H.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
=> these are the square of binomials: and
Important to know:
If the binomial has a minus sign, then the minus sign appears of the trinomial.
If the binomial is , then the middle term will be ,
and if the binomial is , then the middle term will be ;
therefore, we can use the (""),
to state the rule as follows:
The square of produces the following three terms:
1. The square of the first term of the binomial:
2. Twice the product of the two terms:
3. The square of the second term:
The square of , called a perfect square trinomial,
has that form: .
So, if your square your binomial , it will be:
is the square of .
is twice the product of .
is the square of .
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