SOLUTION: The notation n! = n�(n-1)�(n�2)� � � � � �3�2�1. For example, 5! = 5�4�3�2�1 = 120. How many zeroes occur at the end of the expanded numeral for 100!?

Question 1115766: The notation n! = n�(n-1)�(n�2)� � � � � �3�2�1. For example, 5! = 5�4�3�2�1 = 120. How many zeroes occur at the end of the expanded numeral for 100!?
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.
It was solved and answered under this link
https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1115588.html

https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1115588.html

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
The number of trailing zeros in the decimal representation of , the factorial of a non-negative integer , can be determined with this formula:
+...+ where must be chosen such that

so, has trailing zeros
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