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A flare is shot upward from the edge of a 88 foot tall cliff with an initial velocity of 82 ft/sec.
What is the maximum height above the ground this flare will go in feet?
Round your answer to 1 decimal place.
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The formula for the height above the cliff base as the function of time is
h(t) = -16t^2 + 82t + 88. (1)
The height is maximum when the quadratic function (1) is maximum.
It happens when t = = = = 2.56 seconds.
At this time, h(t) = -16*2.56^2 + 82*2.56 + 88 = 193.1 ft.
Answer. The maximum height above the cliff base is 193.1 ft.
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On finding the maximum/minimum of a quadratic function see the lessons
- HOW TO complete the square to find the minimum/maximum of a quadratic function
- Briefly on finding the minimum/maximum of a quadratic function
- HOW TO complete the square to find the vertex of a parabola
- Briefly on finding the vertex of a parabola
in this site.
To see other similar solved problems on a projectile thrown/shot/launched vertically up, look into the lessons
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
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I wrote my text to fix an error in the @KMST calculation of the time to get the maximum height.