SOLUTION: We think we have the answer, but the answer does not appear on the worksheet as a possible solution. A set of children's blocks contains 3 shapes, longs, flats & cubes. There a

Question 111232: We think we have the answer, but the answer does not appear on the worksheet as a possible solution.
A set of children's blocks contains 3 shapes, longs, flats & cubes. There are 3 times as many longs as cubes and 30 fewer flats than longs. If there are 600 blocks in all, how many longs are there?
600 = c + l + f
c = 3l
f = l -30
600 = 3l + l + l-30
600 = 5l - 30
630 = 5l
l = 126
Is this correct, or has something been transposed?
Found 3 solutions by checkley71, josmiceli, solver91311:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
YOUR WORK LOOKS GOOD. NOW DO THE PROOF.
600=126+126*3+(126-30)
600=126+378+96
600=600 VOILA! THE ANSWERS CHECK.
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Think about your basic assumptions. The problem says
there are 3 times as many longs as cubes. So, if L = longs
and C = cubes, then l is quite a bit bigger than C.
But you said , which makes C three times bigger than L.
this is correct
same as yours

answer
check answer

OK

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
Your first and third equations are correct, but the second one should be .
:
That makes your first substitution equation:

:
So, 270 long blocks, 90 cubes, and 240 flats.
270 is three times 90 and 30 more than 240, and 270+90+240=600, so the answer checks.
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